Polyconvexity

Last review: 28/03/2021 17:40

$\varphi(\bf F)$ is said to be polyconvex if

\varphi(F)=\widehat\varphi(\bm F, \operatorname{cof} \bm F, \operatorname{det} \bm F)

$\widehat\varphi$ which is convex with respect to the components of its arguments. ¹

$\newcommand\bm{\boldsymbol}$

1 the function

$\widehat\varphi$ depends, totally, on

$\mathbb R^{\left(\frac {2d} {d}\right)-1}$ where

$d$ is the dimension. ↩